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Chemical Properties of Alkanes

n- factor of ...

Question

$n -$ factor of $P_{4} O_{6}$ in the change, $P_{4} O_{6} ⟶ H_{3} P O_{4}$ , is :

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Solution

$P_{4} O_{6} ⟶ H_{3} P O_{4}$
+3 +5
Change in oxidation state of P $= 5 - 3 = 2$
So, $n$ -factor of $P_{4} O_{6} = 2 \times 4 = 8$ .

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