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Antiderivative

N(g) + O+(g...

Question

N(g) + O+(g) ---> N+(g) + O(g) is the above process spon†an eous?

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Solution

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O_{(g)}

O_{(g)}^{-}

N e_{(g)}

N e_{(g)}^{+}

O_{(g)}^{+}

O_{(g)}

N_{(g)}

N_{(g)}^{+}

O (g) + e^{-} ⟶ O^{-} (g), △ H_{e g} = - v e

O^{2 -} (g)

O (g) + e^{-} = O^{-} (g); Δ H^{0} = - 142 k J m o 1^{- 1}

O (g)^{-} + e^{-} = O^{2 -} (g); Δ H^{0} = 844 k J m o 1^{- 1}

O^{2 -} (g)

O (g) + e^{-} \to O^{-} (g); △ H^{o} = - 142 k J m o l^{- 1}

O (g) + e^{-} \to O^{2 -} (g); △ H^{o} = - 844 k J m o l^{- 1}

_{(g)}^{2 -}

O_{(g)} + e^{-} \to O_{(g)}^{-}; Δ H^{\circ} = - 141 k J m o l^{- 1}

O_{(g)}^{-} + e^{-} \to O_{(g)}^{2 -}; Δ H^{\circ} = + 780 k J m o l^{- 1}

O^{2 -}

O^{2 -}

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