Question

$N-H$ Bond in ammonia molecule is:

• A. $\sigma s-s$
• B. $\sigma p-s$
• C. $\sigma s{p}^3-s$
• D. $\sigma s{p}^3-p$

Answer 1

The correct option is C $\sigma s{p}^3-s$

Ammonia has $3$ bond pairs and $1$ lone pair. The hybridization is $s{p}^3$. Since $H$ has no $p$ orbital, so it has to be $s$. And the bond is sigma and not pi.