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Quantitative Aptitude

Number of Zeroes in a Number

N! has 37 zer...

Question

N! has 37 zeroes at its end. How many values of N is/are possible?

A

1

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B

5

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C

Infinite

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Solution

The correct option is B 5
N! is having 37 zeroes at its end, and therefore, N = 150 (can be arrived by, 150/5 + 150/25 + 150/125.)
Obviously, $150 \leq N < 155$ is the answer.

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