1
Question
N! has 37 zeros at its end. How many values of N is/are possible?
N! has 37 zeros at its end. How many values of N is/are possible?
Open in App
Solution
The correct option is B 5
N! is having 37 zeros at its end, so N = 150 (obtained by Hit and Trial as N is approximately four times the number of zeros)
So, 150≤N≤154, as all will contain same number of powers of 5.
So, five values are possible.
N! is having 37 zeros at its end, so N = 150 (obtained by Hit and Trial as N is approximately four times the number of zeros)
So, 150≤N≤154, as all will contain same number of powers of 5.
So, five values are possible.
Suggest Corrections
0
Similar questions
View More
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program
