n-heptane when heated to a temperature of about 773 K under high pressure in the presence of $C r_{2} O_{3} / A l_{2} O_{3}$ catalyst gives -

Ethylbenzene

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1,2-dimethylbenzene

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Benzene

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Methylbenzene(Toluene)

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Solution

The correct option is D Methylbenzene(Toluene)
Aromatization:The n-alkanes with 6 or more C atoms, on heating to 773 K at 10-20 atm pressure in the presence of oxides of V/Mo/Cr get dehydrated and cyclised to form benzene and its derivatives.
$C_{7} H_{16} n-heptane C r_{2} O_{3} / A l_{2} O_{3}, 10 - 20 a t m - -------------- \to △ (773 K) C_{6} H_{5} C H_{3} Methylbenzene(Toluene)$

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Similar questions

C r_{2} O_{3} / A l_{2} O_{3}

C r_{2} O_{3} / A l_{2} O_{3}

C r_{2} O_{3} / A l_{2} O_{3}

C r_{2} O_{3} / A l_{2} O_{3}

(A l_{2} O_{3} + C r_{2} O_{3})

773 K

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