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Question

n'is selected from the set 1,2,3,...,100 and the number 2n+3n+5n is formed. Total number of ways of selecting 'n' so that the formed number is divisible by 4, is equal to


A

50

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B

49

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C

48

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D

None of these

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Solution

The correct option is B

49


Explanation for the correct option :

Finding the total number of ways of selecting 'n' so that the formed number is divisible by 4, is equal to,

On dividing 2n by 4 we get 2 as reminder when n=1and0of rest value of n

On dividing 3n by 4 we get 3 as reminder when n is odd and 1 as reminder when n is even.
On dividing 5n by 4 we get 1 as reminder for all value of n.

2n+3n+5nis divisible by 4 only when

reminder on dividing 2n by 4+reminder on dividing 3n by 4+ reminder on dividing 5n by 4= a multiple of 4

This is possible for all odd n except 1 because for all odd n sum of reminders =0+3+1=4

Forn=1 we have sum of reminder=2+3+1=6

So our answer will be all odd number except 1 which is equal to 49

Hence ,the correct answer is option (B).


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