The correct option is A True
(a,b)∼(c,d) iff ad=bc
Reflexivity:
We can write ab=ab
⇒(a,b)∼(a,b) (by given def)
Hence, ∼ is reflexive.
Symmetry:
Let (a,b)∼(c,d)
⇒ad=bc
⇒da=cb (Product of real numbers is commutative)
orcb=da
⇒(c,d)∼(a,b)
Hence, ∼ is symmetric.
Transitivity:
Let (a,b)∼(c,d);(c,d)∼(e,f)
⇒ad=bc;cf=de
⇒af=be (Since dc=fe)
⇒(a,b)∼(e,f)
Hence, ∼ is transitive.
Hence, ∼ is an equivalence relation.