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Standard XII

Physics

Matter Waves

N molecules e...

Question

N molecules each of mass m, of gas A and 2N molecules each of mass 2m, of gas B are contained in the same vessel which is maintained at a temperature T. The mean square velocity of molecules of B type is denoted by $V_{2}$ and the mean square velocity of A type is denoted by $V_{1}$ , then $\frac{V_{1}}{V_{2}}$ is

1

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Solution

The correct option is C 1 $/ 2$
Mean square velocity of $A = \frac{3 K T}{m} \to (i)$

Mean square velocity of $B = \frac{3 K T}{2 m} \to (i i)$
$\frac{v_{1}}{v_{2}} = \frac{\frac{3 K T}{m}}{\frac{3 K T}{2 m}} = \frac{1}{2}$

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N molecules each of mass m, of gas A and 2N molecules each of mass 2m, of gas B are contained in the same vessel which is maintained at a temperature T. The mean square velocity of molecules of B type is denoted by V2 and the mean square velocity of A type is denoted by V1, then V1V2 is

The correct option is C 1/2Mean square velocity of A=3KTm→(i)Mean square velocity of B=3KT2m→(ii)v1v2=3KTm3KT2m=12

The correct option is C 1 $/ 2$
Mean square velocity of $A = \frac{3 K T}{m} \to (i)$

Mean square velocity of $B = \frac{3 K T}{2 m} \to (i i)$
$\frac{v_{1}}{v_{2}} = \frac{\frac{3 K T}{m}}{\frac{3 K T}{2 m}} = \frac{1}{2}$