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Question

# n moles of a gas filled in a container is in thermodynamic equilibrium initially at temperature T. If the gas is compressed quasi-statically and isothermally to half of its initial volume, the work done on the gas is :

A
nRT2
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B
nRT2
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C
nRT(ln212)
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D
nRTln 2
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Solution

## The correct option is D nRTln 2Work done by the gas filled in a container in a isothermal process is given by W=nRTln(VfVi) ......(1) Let the initial volume of gas (Vi) be V ∴ from the data given in the question we can say that, Final volume of gas (Vf)=V2 From (1), W=nRTln(V/2V) Thus we get, work done by the gas W=nRTln(12) W=−nRTln2 So, work done on the gas is W=nRTln2 Thus, option (d) is the correct answer.

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