Question

‘n’ moles of an ideal gas undergoes a process $A\to B$ as shown in the figure. The maximum temperature of the gas during the process will be:

• A.
• B.
• C.
• D.

Answer 1

The correct option is D

$p=\frac{-P0}{V0}V+3P_0$

$T=\frac{-P_0{v}^2}{V_{0}nR}+\frac{3P_{0}V}{nR}$ ……(1)

For $T_{max}$

$\frac{dT}{dv}=0$

$\Rightarrow v=\frac{3}{2}{v}_0$ ...............(2)

Using (1) and (2)

$T_{max}=\frac{9}{4}\frac{P_0{V}_{­}0}{nR}$