'n' numbers of resistors each of resistance 'R' are first connected in series and then in parallel. What would be the ratio of the equivalent resistance $(\frac{R_{s}}{R_{p}})$ of the two cases?

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n²

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n³

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None of these

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Solution

The correct option is B
n²

In series net resistance $(R_{s}) = n R$

In parallel net resistance $(R_{p}) = \frac{R}{n}$

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