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Standard XII

Chemistry

Nitrous Oxide

N O 2 general...

Question

$N O_{2}$ generally exists as a dimer which is colourless unlike $N O_{2}$ . Justify.

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Solution

${N O}_{2}$ is an odd electron molecule.In this central atom ( $N$ ) is one electron short to complete its octate so ${N O}_{2}$ molecule readily combines with another ${N O}_{2}$ molecule to form dimer.
Due to this pairing of electron ${N O}_{2}$ loses its color and the dimer becomes colorless.

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Similar questions

Q. Assertion :

N O_{2}

is reddish brown and its dimer

N_{2} O_{4}

is colourless. Reason: There is a dative bond formation between two

N O_{2}

molecules.

A gas bulb is filled with $N O_{2}$ gas and immersed in an ice bath at $0^{\circ} C$ which becomes colourless after sometimes. This colourless gas will be

Q. Assertion :On cooling, the brown colour of

N O_{2}

disappears. Reason: On cooling

N O_{2}

forms dimer

(N_{2} O_{4})

resulting in the pairing of the odd electrons in

N O_{2}

Q. Of the following statements which are true for

N O_{2}

i)

Nitrogen dioxide brown liquid turns pale on cooling and becomes colourless solid
ii)

N O_{2}

undergoes dimerisation to form

N_{2} O_{4}

iii)

N O_{2}

is paramagnetic,

N_{2} O_{4}

is diamagnetic

Q. Which of the following statements about the monomer and dimer of

N O_{2}

are not true ?

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NO2 generally exists as a dimer which is colourless unlike NO2. Justify.

NO2 is an odd electron molecule.In this central atom (N) is one electron short to complete its octate so NO2 molecule readily combines with another NO2 molecule to form dimer. Due to this pairing of electron NO2 loses its color and the dimer becomes colorless.

$N O_{2}$ generally exists as a dimer which is colourless unlike $N O_{2}$ . Justify.

${N O}_{2}$ is an odd electron molecule.In this central atom ( $N$ ) is one electron short to complete its octate so ${N O}_{2}$ molecule readily combines with another ${N O}_{2}$ molecule to form dimer.
Due to this pairing of electron ${N O}_{2}$ loses its color and the dimer becomes colorless.