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Question

nLt[11+n3+48+n3+927+n3+.+12n]=

A
12log2
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B
13log3
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C
13log2
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D
12log3
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Solution

The correct option is A 13log2

nLt[1(1+n3)+4(8+n3)+9(27+n3)+.......n2(n3+n3)]
nLtnr=1r2r3+n3=nLtnr=11n(rn)2(rn)3+1
=10x2x3+1dx=1321dx31+x3
=13log(1+x3)10
=13[log(2)]
=13log2


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