n-pentane and iso pentane can be distinguished by

{K M n O}_{4}

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conc.

H_{2} {S O}_{4}

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O_{3}

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{B r}_{2}

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Solution

The correct option is A ${K M n O}_{4}$
On oxidation with $K M n O_{4}$ both n-pentane and iso-pantene give different alcohols.

n-pantene give 1° alcohol where has iso-pentane give 3°alcohol.

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