n-Propyl alcohol is obtained on hydrolysis of the adduct obtained by the reaction of:

EtMgX and HCHO

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MeMgX and

(C H_{2})_{2} O

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EtMgX and

O_{2}

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MeMgX and

C H_{3} C H O

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Solution

The correct option is A EtMgX and HCHO
Ethyl magnesium bromide reacts with formaldehyde to form an adduct which on hydrolysis gives 1-Propanol.
${C H}_{3} {C H}_{2} M g B r + H C H O \to ({C H}_{3} {C H}_{2} {C H}_{2} O M g B r) a d d u c t \to {C H}_{3} {C H}_{2} {C H}_{2} O H 1 - P r o p a n o l$

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