n−PropylchloridealcKCN−−−−−→(P)H3O+−−−→(Q)
Which statement is not true about the compounds P and Q?
A
P on reduction gives butanamine
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B
Q is butanoic acid
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C
Q on decarboxylation gives propane
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D
P is propanenitrile
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Solution
The correct option is D P is propanenitrile CH3CH2CH2ClalcKCN−−−−−→CH3CH2CH2CNH3O+−−−→CH3CH2CH2COOH
P is butanenitrile which upon reduction gives butanamine.