$N a_{2} [B e (O H_{4})]$ is formed when :

B e O

reacts with

N a O H

solution.

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B e

reacts with

N a O H

solution.

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both A and B.

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none of the above.

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Solution

The correct option is B both A and B.
Reactions are as follows:
$B e O + 2 N a O H + H_{2} O \to N a_{2} [B e (O H)_{4}]$
$B e + 2 N a O H + 2 H_{2} O \to N a_{2} [B e (O H)_{4}] + H_{2}$

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