$N a_{2} B_{4} O_{7} .10 H_{2} O +$ conc. $H_{2} S O_{4} △ ⟶ (A) C H_{3} O H, △ ⟶$ (B)
(A) and (B) are $H_{3} B O_{3}$ and $(C H_{3})_{3} B O_{3}$ respectively.
If true enter 1, if false enter 0.

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Solution

$(A)$ is $H_{3} B O_{3}$ and $(B)$ is methyl borate,
$(C H_{3})_{3} B O_{3}$ burns with green edged flame.
$N a_{2} B_{4} O_{7} . 10 H_{2} O +$ conc. $H_{2} S O_{4} △ ⟶ H_{3} B O_{3} (A) C H_{3} O H, △ ⟶ (C H_{3})_{3} B O_{3} B$

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