Na2B4O7-10H2O X Y-Z X- Y and Z in the reaction are -

The correct option is A X=Na_2B_4O_7, Y=NaBO_2,Z=B_2O_3 Answer: Na_2B_4O_7.10H_2O XNa_2B_4O_7 Y2NaBO_2 + ZB_2O_3 Thus, (A) is correct answer. ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Borax

Na2B4O7.10H2O...

Question

$N a_{2} B_{4} O_{7} .10 H_{2} O △ - \to X △ - \to Y + Z$ X, Y and Z in the reaction are :

X = N a_{2} B_{4} O_{7}, Y = N a B O_{2}, Z = B_{2} O_{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

X = N a_{2} B_{4} O_{7}, Y = B_{2} O_{3}, Z = H_{3} B O_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

X = N a_{2} B_{4} O_{7}, Y = N a B O_{2}, Z = B (O H)_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

X = N a B O_{2}, Y = B_{2} O_{3}, Z = B (O H)_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

N a_{2} B_{4} O_{7} .10 H_{2} O H e a t - -- \to X + N a B O_{2} + H_{2} O

X + C r_{2} O_{3} H e a t - -- \to Y G r e e n c o l o u r

X

Y

$N a B O_{2} + C O_{2} \to A + B$ . A & B are as follows

N a_{2} B_{4} O_{7} .10 H_{2} O 720^{o} C - --- \to Δ 2 N a B O_{2} + (X) + 10 H_{2} O

(X) + C a F_{2} + H_{2} S O_{4} ⟶ (Y) + C a S O_{4} + H_{2} O

(Y) + N a B H_{4} ⟶ (Z) + N a B F_{4}

(Z) High temperature - --------- \to N H_{3} (1 : 2) B_{3} N_{3} H_{6} Inorganic benzene

(X), (Y)

(Z)

If x, y and z are variables, verify the cyclic symmetry of the following expressions.

(1) x(y + z) + y(z + x) + z(x + y)

(2) xy(x − y) + yz(y − z) + zx(z − x)

(3) x²y(x + y) + y²z(y + z) + z²x(z + x)

(4) x³(x + y) + y³(y + z) + z³(z + x)

(5) xy²(x − y) + yz²(y − z) + zx²(z − x)

If $\frac{x (y + z - x)}{l o g x} = \frac{y (z + x - y)}{l o g y} = \frac{z (x + y - z)}{l o g z}$ , then $x^{y} y^{x} = z^{y} y^{z} = x^{z} z^{x}$

Join BYJU'S Learning Program