N a 2 B 4 O 7-2 HCl - 2 N aCl - AN a 2 B 4 O 7- H 2 SO 4- N a 2 SO 4- A - A is as follows-A- None of theseB- H 3 BO 3C- H2 B4 O7D- H3 B O4

The correct option is C Na_2B_4O_7+2HCl ⟶ 2NaCl+H_2B_4O_7 Na_2B_4O_7+H_2SO_4 → Na_2SO_4+H_2B_4O_7 ...

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Reactivity with Halogens and Hydrogen (Group 2)

N a 2 B 4 O 7...

Question

$N a_{2} B_{4} O_{7} + 2 H C l ⟶ 2 N a C l + A$

$N a_{2} B_{4} O_{7} + H_{2} S O_{4} \to N a_{2} S O_{4} + A$ . A is as follows:

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Solution

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Similar questions

$N a_{2} B_{4} O_{7} + 2 H C l ⟶ 2 N a C l + A$

$N a_{2} B_{4} O_{7} + H_{2} S O_{4} \to N a_{2} S O_{4} + A$ . A is?

$B + H_{2} S O_{4} \to A + S O_{2}$

$B + H N O_{3} \to A + N O_{2} A$ is

H C l

N a C l

H_{2} S O_{4}

2 N a C l + H_{2} S O_{4} \to N a_{2} S O_{4} + 2 H C l

74.1 %

N a_{2} S O_{4}

245

93.9 %

N a C l

2 N a C l + H_{2} S O_{4} ⟶ N a_{2} S O_{4} + 2 H C l

(N a_{2} S O_{4})

2 N a C l + H_{2} S O_{4} \to N a_{2} S O_{4} + 2 H C l

100.0

90 %

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