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Stoichiometric Calculations

N a 2 B 4 O 7...

Question

$N a_{2} B_{4} O_{7} + 2 H C l ⟶ 2 N a C l + A$

$N a_{2} B_{4} O_{7} + H_{2} S O_{4} \to N a_{2} S O_{4} + A$ . A is?

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Similar questions

$N a_{2} B_{4} O_{7} + 2 H C l ⟶ 2 N a C l + A$

$N a_{2} B_{4} O_{7} + H_{2} S O_{4} \to N a_{2} S O_{4} + A$ . A is as follows:

$B + H_{2} S O_{4} \to A + S O_{2}$

$B + H N O_{3} \to A + N O_{2} A$ is

74.1 %

N a_{2} S O_{4}

245

93.9 %

N a C l

2 N a C l + H_{2} S O_{4} ⟶ N a_{2} S O_{4} + 2 H C l

H C l

N a C l

H_{2} S O_{4}

2 N a C l + H_{2} S O_{4} \to N a_{2} S O_{4} + 2 H C l

(N a_{2} S O_{4})

2 N a C l + H_{2} S O_{4} \to N a_{2} S O_{4} + 2 H C l

100.0

90 %

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