Question

$N{a}_2{B}_4{O}_7+X\to H_{3}B{O}_3$. What is X in the reaction?

• A. Aqueous Solution of NaOH
• B. Dilute nitric acid
• C. Conc. $H_{2}S{O}_4$ or HCl
• D. Water

Answer 1

The correct option is C Conc. $H_{2}S{O}_4$ or HCl

Answer:- (C) Conc. $H_{2}S{O}_{4}orHCl$

Reaction of ${Na}_2{B}_4{O}_7\text{with conc.}{H}_{2}S{O}_4\to$

${Na}_2{B}_4{O}_7+\underset{\left(X\right)}{\underset{Conc.}{H_{2}S{O}_4}}+5H2O⟶{Na}_{2}S{O}_4+4H_{3}B{O}_3$

Reaction of ${Na}_2{B}_4{O}_{7}withHCl\to$

${Na}_2{B}_4{O}_7+\underset{\left(X\right)}{2HCl}+5H_{2}O⟶2NaCl+4H_{3}B{O}_3$

Thus, (C) is correct answer.