Question

$N{a}_{2}C{O}_3$ can be manufactured by Solvay's process but $K_{2}C{O}_3$ cannot be prepared because:

• A. $K_{2}C{O}_3$ is more soluble than $N{a}_{2}C{O}_3$
• B. $K_{2}C{O}_3$ is less soluble than $N{a}_{2}C{O}_3$
• C. $KHC{O}_3$ is more soluble than $NaHC{O}_3$
• D. $KHC{O}_3$ is less soluble than $NaHC{O}_3$a
• E. None of the above

Answer 1

The correct option is B $K_{2}C{O}_3$ is less soluble than $N{a}_{2}C{O}_3$

$N{a}_{2}C{O}_3$ can be manufactured by Solvay's process by the reaction of Nacl and $CaC{O}_3$ which gives insoluble precipitate of $N{a}_{2}C{O}_3$.But $K_{2}C{O}_3$ cannot be prepared because as it is soluble and can't be separated out.
Hence option B is correct.