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Question

$$ Na_2CO_3 $$ can be manufactured by Solvay's process but $$ K_2CO_3 $$ cannot be prepared because:


A
K2CO3 is more soluble than Na2CO3
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B
K2CO3 is less soluble than Na2CO3
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C
KHCO3 is more soluble than NaHCO3
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D
KHCO3 is less soluble than NaHCO3a
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E
None of the above
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Solution

The correct option is B $$ K_2CO_3 $$ is less soluble than $$ Na_2CO_3 $$
$$ Na_2CO_3 $$ can be manufactured by Solvay's process by the reaction of Nacl and $$CaCO_3$$ which gives insoluble precipitate of  $$ Na_2CO_3 $$.But $$ K_2CO_3 $$ cannot be prepared because as it is soluble and can't be separated out.
Hence option B is correct.

Chemistry

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