N a 2 CO 3- H 2 O when exposed to air looses water of crystallization and gives finallyA- Na 2 CO 3 -4 H 2 OB- Na 2 CO 3- H 2 OC- Na 2 CO 3- 7 H 2 OD- Na 2 CO 3 -9 H 2 O

The correct option is B Na2CO3.H2O Na_2CO_3 is efflorescent and looses 9 water molecules on exposure to air ...

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N a 2 CO 3· H...

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$N a_{2} C O_{3} . H_{2} O$ when exposed to air looses water of crystallization and gives finally

Na₂CO₃.4H₂O

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Na₂CO₃.H₂O

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Na₂CO₃.7H₂O

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Na₂CO₃.9H₂O

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