$N a_{2} C O_{3}$ reacts with $S O_{2}$ and produces :

N a_{2} S O_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N a_{2} S O_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N a H S O_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N a H S O_{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is C $N a H S O_{3}$
$N a_{2} C O_{3}$ reacts with $S O_{2}$ and produces $N a H S O_{3}$ .

The reaction is as follows:
$N a_{2} C O_{3} + H_{2} O + 2 S O_{2} \to 2 N a H S O_{3} + C O$

Suggest Corrections

Similar questions

N a_{2} C O_{3} S O_{2} - - \to (A) N a_{2} C O_{3} - ---- \to (B) S \to (C) A g N O_{3} - --- \to (D)

_{4}

H_{2} S O_{4}

N a_{2} C O_{3}, N a H C O_{3}, N a_{2} S O_{3}, N a_{2} S, N a_{2} S_{2} O_{3}, N a_{2} S O_{4}, N a N O_{2}

N a I O_{3} + N a H S O_{3} \to N a_{2} S O_{4} + N a H S O_{4} + I_{2} + H_{2} O

S O_{2}

S O_{2}

N a_{2} C O_{3}

N a_{2} S O_{3}

Join BYJU'S Learning Program