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Percentage Composition

Na2SO3· xH2O ...

Question

$N a_{2} S O_{3} \cdot x H_{2} O$ has $50 %$ $H_{2} O$ by mass. Hence, $x$ is :

4

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Solution

The correct option is D $7$
Molecular mass of $N a_{2} S O_{3} \cdot x H_{2} O = 126 + 18 x$
Hence, $\frac{18 x}{126 + 18 x} = 0.5$ (given)
$∴ x = 7$

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