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Variation of G Due to Height and Depth

Na2SO4. xH2O ...

Question

$N a_{2} S O_{4} . x H_{2} O$ has $50 %$ $H_{2} O$ . Hence, $x$ is :

4

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5

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8

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Solution

The correct option is D $8$
The molar mass of $N a_{2} S O_{4}$ is $142$ g/mol.
The molar mass of $N a_{2} S O_{4} . x H_{2} O$ is $142 + 18 x$ g/mol. Since, $50 %$ water is present,
$\frac{142 + 18 x}{2} = 18 x$
$36 x = 142 + 18 x$
$18 x = 142$
$x = 7.9 ≃ 8$

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