In the formation of cation, the radius of the cation is generally smaller than its atom. For Na, when it loses an electron, its outer shell will be removed thus having a smaller ionic radius. It will have a similar configuration to that of Neon.
The electronic configuration for Na atom is 2,8,1 (z=11) and electronic configuration for Na ion is 2,8 (z=10). There is a removal of the m shell and hence, the ion is smaller in size. After removal of one electron, the effective nuclear charge on sodium atoms increase due to which nucleus tends to attract the electrons with a greater force and thus, causing a shrink in size.
Hence, the statement is correct and correct answer is 1.