$N a + C l \to N a^{+} + C l^{-} \to N a^{+} C l^{-}$
(2,8,1) (2,8,7) (2,8) (2,8,8)
The above equation represents the formation of sodium chloride. Observe the equation and answer the following:
a) How many electrons are transferred from $N a$ to $C l$ ?
b) Name the force acting between $N a^{+}$ and $C l^{-}$ .
c) Name the nearest noble gas to $C l^{-}$ .
d) Name the bond between $N a^{+}$ and $C l^{-}$ .
e) How many electrons are present in $N a^{+}$ ion?

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Solution

(a) One $e^{-}$ (by doing this ${N a}^{+}$ is nobel gas ${1 S}^{2} {2 S}^{2} {2 P}^{6}$ )
(b) electrostatic force of attraction between ${N a}^{+} a n d {C l}^{-}$ .
(c) Argon $(18)$ $({1 S}^{2} {2 S}^{2} 2 P^{6} {3 S}^{2} {3 P}^{6}) = {C l}^{-}$
(d) Ionic or electovalent bond
(e) $10 e^{-} ({1 S}^{2} {2 S}^{2} {2 P}^{6})$ , (Since it lost one electron)

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