$N a$ is used in reduction of $Z n$ salt because:

E Z n (o x i) > E N a (o x i)

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E Z n (r e d) < E N a (r e d)

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E Z n (o x i) < E N a (o x i)

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Both (A) and (B)

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Solution

The correct option is D $E Z n (o x i) < E N a (o x i)$
Metals having higher oxidation potential (or lesser $E_{r e d}$ ) can replace metals having lesser oxidation potential.
$∵$ Oxidation potential of $N a$ is more than that of $Z n$ .
$∴ N a$ is used to reduce $Z n$ salts.

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Na is used in reduction of Zn salt because:

The correct option is D EZn(oxi)<ENa(oxi)Metals having higher oxidation potential (or lesser Ered) can replace metals having lesser oxidation potential.∵ Oxidation potential of Na is more than that of Zn.∴Na is used to reduce Zn salts.

$N a$ is used in reduction of $Z n$ salt because:

The correct option is D $E Z n (o x i) < E N a (o x i)$
Metals having higher oxidation potential (or lesser $E_{r e d}$ ) can replace metals having lesser oxidation potential.
$∵$ Oxidation potential of $N a$ is more than that of $Z n$ .
$∴ N a$ is used to reduce $Z n$ salts.