$N a^{+}, M g^{2 +}, A l^{3 +}$ and $S i^{4 +}$ are isoelectronic ions. Their ionic size will follow the order:

N a^{+} < M g^{2 +} < A l^{3 +} < S i^{4 +}

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N a^{+} > M g^{2 +} < A l^{3 +} < S i^{4 +}

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N a^{+} < M g^{2 +} > A l^{3 +} > S i^{4 +}

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N a^{+} > M g^{2 +} > A l^{3 +} > S i^{4 +}

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Solution

The correct option is D $N a^{+} > M g^{2 +} > A l^{3 +} > S i^{4 +}$

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Similar questions

N a^{+}

M g^{2 +}

A l^{3 +}

S i^{4 +}

$N a^{+} . M g^{2 +}, A l^{3 +}$ and $S i^{4 +}$ are isoelectronic. The order of their ionic size is

N a^{+}, M g^{2 +}, A l^{3 +}

S i^{4 +}

$N a^{+} . M g^{2 +}, A l^{3 +}$ and $S i^{4 +}$ are isoelectronic. The order of their ionic size is

O^{2 -}, F^{-}, N a^{+}, M g^{2 +}

A l^{3 +}

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