Question

Na⁺ have completely filled K and L shells explain.

Answer 1

Na⁺ have completely filled K and L shells:

1. Sodium is a alkali metal. The main claim to fame of this substance is that it is one of the two components of table salt.
2. Atomic number of Sodium ($\mathrm{Na}$) = 11
   Number of electrons in Sodium ($\mathrm{Na}$) = 11
   Sodium's [$\mathrm{Na}$] electronic structure is $1{\mathrm{s}}^{2}2{\mathrm{s}}^{2}2{\mathrm{p}}^{6}4{\mathrm{s}}^1$.
3. In order to form a positive ion, $\mathrm{Na}$loses one electron. Therefore, ${\mathrm{Na}}^{+}$ ion possesses 10 electrons, which is one more than the Na atom. As a result, 2 electrons move to the K-shell and 8 to the L-shell, entirely filling both shells.
   The number of electrons in ${\mathrm{Na}}^{+}$is calculated as 11 - 1 = 10.
   electronic structure is $1{\mathrm{s}}^{2}2{\mathrm{s}}^{2}2{\mathrm{p}}^6$
   K and L shells are thus fully filled in Na+.

Therefore, ${\mathrm{Na}}^{+}$ has completely filled K and L shells.