NaBH4 - I2 - X - Y - Z BF3 - NaH X - P BF4 - LiAlH4 - X - Q - R Identify X- Y- Z- P and Q-

The correct options are B X B_2H_6, Y NaI C Z = H_2, P = NaF D Q = nbsp;3Li[AlF_4]X = B_2H_6, Y = NaI, Z = H_2, P = NaF, Q = nbsp;3Li[AlF_4] Sodium borohy ...

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Byju's Answer

Standard XII

Chemistry

Diborane

NaBH4 + I2 → ...

Question

$N a B H_{4} + I_{2} \to X + Y + Z$
$B F_{3} + N a H 450 K - -- \to X + P$
$B F_{4} + L i A l H_{4} \to X + Q + R$
Identify $X, Y, Z, P and Q .$

X - N a_{4} B_{4} O_{7}, Y - N a I

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X - B_{2} H_{6}, Y - N a I

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Z = H_{2}, P = N a F

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Q = 3 L i [A l F_{4}]

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Solution

The correct options are
B $X - B_{2} H_{6}, Y - N a I$
C $Z = H_{2}, P = N a F$
D $Q = 3 L i [A l F_{4}]$
$X = B_{2} H_{6}, Y = N a I, Z = H_{2}, P = N a F, Q = 3 L i [A l F_{4}]$
Sodium borohydrate react with iodine to produce diborane, sodium iodide and hydrogen.
The reaction proceeds in the digilyme $(M e O C H_{2} C H_{2})_{2} O .$
$2 N a [B H_{4}] + I_{2} (M e O C H_{2} C H_{2})_{2} O - ---------- \to B_{2} H_{6} + 2 N a I + H_{2}$
Thus, $X = B_{2} H_{6}, Y = N a I, Z = H_{2}$
Boron trifluoride reacts with sodium hydride to give diborane and sodium fluoride. This reaction takes place at a temperature around $200^{o} C .$
$2 B F_{3} + 6 N a H ≃ 200^{o} C - ---- \to B_{2} H_{6} + 6 N a F$
Thus, $P = N a F$
Boron trifluoride on reaction with Lithium aluminium hydride produces diborane, lithium fluoride and aluminium fluoride.
$4 B F_{3} + 3 L i A l H_{4} \to 2 B_{2} H_{6} + 3 L i [A l F_{4}]$
Thus, $Q = L i [A l F_{4}]$

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Similar questions

N a B H_{4} + I_{2} \to X + Y + Z

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Diborane

Standard XII Chemistry

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NaBH4+I2→X+Y+Z BF3+NaH450K−−−→X+P BF4+LiAlH4→X+Q+R Identify X,Y,Z,P and Q.

$N a B H_{4} + I_{2} \to X + Y + Z$
$B F_{3} + N a H 450 K - -- \to X + P$
$B F_{4} + L i A l H_{4} \to X + Q + R$
Identify $X, Y, Z, P and Q .$