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Question

NaBH4+I2X+Y+Z
BF3+NaH450K−−X+P
BF3+LiAlH4X+Q+RIdentify X, Y, Z, P and Q.

A
XNa4B4O7,YNaI,ZHI,PHF,QLiF,RAlF3
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B
XB2H6,YNaI,ZH2,PNaF,QLiF,RAlF3
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C
XB2H6,YBH3,ZNal,PB3N3H6,QAl2F6,RAlF3
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D
XBH3,YB2H6,ZH2,PB3N3H6,QLiF,RAlF3
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Solution

The correct option is B XB2H6,YNaI,ZH2,PNaF,QLiF,RAlF3
Answer:- (B) X=B2H6,Y=NaI,Z=H2,P=NaF,Q=LiF,R=AlF3
Sodium tetrahydroxoborate(III) react with iodine to produce diborane, sodium iodide and hydrogen.
The reaction proceeds in the diglyme (MeOCH2CH2)2O.
2Na[BH4]+I2(MeOCH2CH2)2O−−−−−−−−−−B2H6+2NaI+H2
Thus, X=B2H6,Y=NaI,Z=H2
Boron trifluoride on reaction with sodium hydride produces diborane and sodium fluoride. This reaction takes place at a temperature near 200°C.
2BF3+6NaH200°C−−−−B2H6+6NaF
Thus, P=NaF
Boron trifluoride on reaction with Lithium Aluminium hydride produces diborane, Lithium Fluoride and Aluminium fluoride.
4BF3+3LiAlH42B2H6+3LiF+3AlF3
Thus, Q=LiF,R=AlF3

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