The correct option is
B X−B2H6,Y−NaI,Z−H2,P−NaF,Q−LiF,R−AlF3Answer:- (B) X=B2H6,Y=NaI,Z=H2,P=NaF,Q=LiF,R=AlF3
Sodium tetrahydroxoborate(III) react with iodine to produce diborane, sodium iodide and hydrogen.
The reaction proceeds in the diglyme (MeOCH2CH2)2O.
2Na[BH4]+I2(MeOCH2CH2)2O−−−−−−−−−−−→B2H6+2NaI+H2
Thus, X=B2H6,Y=NaI,Z=H2
Boron trifluoride on reaction with sodium hydride produces diborane and sodium fluoride. This reaction takes place at a temperature near 200°C.
2BF3+6NaH≃200°C−−−−−→B2H6+6NaF
Thus, P=NaF
Boron trifluoride on reaction with Lithium Aluminium hydride produces diborane, Lithium Fluoride and Aluminium fluoride.
4BF3+3LiAlH4⟶2B2H6+3LiF+3AlF3
Thus, Q=LiF,R=AlF3