$N a C l + H_{2} S O_{4} ⟶ N a H S O_{4} + H C l$

This reaction occurs when temperature is :

less than

200^{\circ} C

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more than

200^{\circ} C

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200^{\circ} C

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None of the above

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Solution

The correct option is A less than $200^{\circ} C$
HCl can be prepared by any of the 2 methods:

1) By synthesis:
Moist hydrogen gas combines with chlorine in the presence of diffused sunlight.
$H_{2} + {C l}_{2} s u n l i g h t - ---- \to d i f f u s e d 2 H C l$

2)By heating metallic chloride with conc. sulfuric acid.
$M e t a l c h l o r i d e + s u l p h u r i c a c i d (c o n c .) \to s a l t + H C l$

$N a C l + H_{2} {S O}_{4} {< 200}^{\circ} C - --- \to {N a H S O}_{4} + {H C l}_{(g)}$
Sodium chloride react with sulfuric acid to produce hydrogen chloride and sodium bisulfate. This reaction takes place at a temperature of $30 - 50^{0} C$ .

Hence, option A is correct.

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200

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