The correct option is A HCl, Br2, I2
Option (B) is correct.
NaCl, NaBr, NaI mixture on adding conc.H2SO4 gives HCl, Br2, I2 gases, respectively.
HBr and HI are strong reducing agents and are oxidized by H2SO4 to Br2 and I2, respectively.
NaCl+conc.H2SO4⟶Na2SO4+HCl
NaBr+conc.H2SO4⟶Na2SO4+Br2+H2O+SO2
NaI+conc.H2SO4⟶Na2SO4+I2+H2O+H2S