Question

Name salts which give brown color or accelerate with Nessler's reagent.

Answer 1

• The salt of Ammonia($\mathit{N}{\mathit{H}}_{\mathbf{3}}$) forms brown color by the reaction with Nessler's reagent. and the salt is Ammonium chloride($\mathit{N}{\mathit{H}}_{\mathbf{4}}\mathit{C}\mathit{l}$).
• The reaction is,

$\underset{Nesslers\text{'}sreagent}{K_{2}Hg{I}_4\left(l\right)}+\underset{Ammoniumchloride}{N{H}_{4}Cl\left(s\right)}+\underset{Potassiumhydroxide}{4KOH\left(l\right)}\to \underset{Brownprecipitate}{NH2-Hg-O-Hg-I\left(s\right)}+\underset{Potassiumiodide}{KI\left(l\right)}+\underset{Potassiumiodide}{KCl\left(l\right)}+H_{2}O\left(l\right)$

• So, the salt is Ammonium chloride.