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Question

Name the following:
(a) Products obtained by dissolving sulphur dioxide and chlorine in water.
(b) The catalyst used in the contact process.
(c) Solution obtained by dissolving sulphur trioxide in 98% sulphuric acid.
(d) Products obtained by treating zinc with dilute sulphuric acid.
(e) Products obtained by treating ferrous sulphide with dilute sulphuric acid.
(f) The precipitate obtained by treating aqueous lead nitrate with dilute sulphuric acid.
(g) The precipitate obtained by treating aqueous barium chloride with dilute sulphuric acid.
(h) Gases obtained by treating carbon with hot concentrated sulphuric acid.
(i) The property used to prepare HCl and HNO3 from H2SO4.

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Solution

(a) Sulphuric acid and hydrochloric acid are obtained by dissolving sulphur dioxide and chlorine in water.
SO2 + 2H2O + Cl2 → H2SO4 + 2HCl
(b) The commonly used catalyst in the contact process is platinum or vanadium pentaoxide. Because platinum is more costly, vanadium pentaoxide is preferred.
(c) Oleum (H2S2O7 ) is obtained by dissolving sulphur trioxide in 98% sulphuric acid.

SO3+ H2SO4 → H2S2O7


(d) On treating zinc with dilute sulphuric acid, zinc sulphate (ZnSO4 ) is formed.

Zn + H2SO4 → ZnSO4 + H2


(e) On treating ferrous sulphide with dilute sulphuric acid, ferrous sulphate and hydrogen sulphide are formed.

FeS + H2SO4 → FeSO4 + H2S


(f) On treating aqueous lead nitrate with dilute sulphuric acid, an insoluble lead sulphate is obtained as the precipitate.

Pb(NO3)2 + H2SO4 → PbSO4↓ + 2HNO3


(g) On treating aqueous barium chloride with dilute sulphuric acid, barium sulphate is obtained as the precipitate.

BaCl2 + H2SO4 → BaSO4↓ + 2HCl


(h) On treating carbon with hot concentrated sulphuric acid, carbon dioxide and sulphur dioxide are formed.

C + 2H2SO4 → 2H2O + 2SO2 + CO2


(i) The non-volatile property of concentrated sulphuric acid is used to prepare HCl and HNO3 from H2SO4.

KCl + conc.H2SO4 →<2000C KHSO4 + HClKNO3 + conc.H2SO4 →<2000C KHSO4 + HNO3



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