Name the gas that can readily decolourise acidified $K M n O_{4}$ solution:

P_{2} O_{5}

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C O_{2}

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S O_{2}

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N O_{2}

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Solution

The correct option is C $S O_{2}$
$S O_{2}$ gas can readily decolourise acidified $K M n O_{4}$ solution. Acidified $K M n O_{4}$ oxidises $S O_{2}$ to $H_{2} S O_{4}$ . $K M n O_{4}$ itself is reduced to $M n O_{2}$ .
$2 K M n O_{4} + H_{2} S O_{4} \to K_{2} S O_{4} + 2 M n S O_{4} + 3 H_{2} O + 5 [O]$
$S O_{2} + [O] + H_{2} O \to H_{2} S O_{4}$ .

Hence, option C is correct.

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