Question

Name the organic compound prepared by each of the following reactions:

${\mathrm{C}}_2{\mathrm{H}}_5\mathrm{Br}+\mathrm{KOH}\left(\mathrm{alcoholic}\right)\to$

Answer 1

1. The chemical name of ${\mathrm{C}}_2{\mathrm{H}}_5\mathrm{Br}$ Bromoethane.
2. The chemical name of $\mathrm{KOH}$ is Potassium hydroxide.
3. Bromoethane (${\mathbf{C}}_{\mathbf{2}}{\mathbf{H}}_{\mathbf{5}}\mathbf{Br}$) on heating with alcoholic solution of Potassium hydroxide ( $\mathbf{KOH}$) to yield Ethene (${\mathbf{CH}}_{\mathbf{2}}\mathbf{=}{\mathbf{CH}}_{\mathbf{2}}$), Potassium bromide ($\mathbf{KBr}$) and water.
4. The reaction is shown below.
   $$\begin{gathered} {\mathrm{C}}_2{\mathrm{H}}_5\mathrm{Br}\left(\mathrm{l}\right)+\mathrm{KOH}\left(\mathrm{l}\right)\underset{∆}{\overset{\mathrm{alcoholic}}{\to }}{\mathrm{CH}}_2={\mathrm{CH}}_2\left(\mathrm{g}\right)+\mathrm{KBr}\left(\mathrm{l}\right)+{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right) \\ \mathrm{Bromo}\mathrm{Potassium}\mathrm{Ethene}\mathrm{Potassium} \\ \mathrm{ethane}\mathrm{hydroxide}\mathrm{bromide} \end{gathered}$$
5. Therefore, the organic compound formed is Ethene.