Question

Name the organic compound prepared in the following reaction:

${\mathrm{C}}_2{\mathrm{H}}_5\mathrm{COONa}+\mathrm{NaOH}\to$

Answer 1

• The product formed in the given reaction is Methane ($C{H}_4$).
• The chemical equation is as follows:

$\underset{\mathrm{Sodium}\mathrm{propanoate}}{{\mathrm{C}}_2{\mathrm{H}}_5\mathrm{COONa}\left(\mathrm{aq}\right)}+\underset{\mathrm{Sodium}\mathrm{hydroxide}}{\mathrm{NaOH}\left(\mathrm{aq}\right)}\to \underset{\mathrm{Methane}}{{\mathrm{CH}}_4\left(\mathrm{g}\right)}+\underset{\mathrm{Sodium}\mathrm{carbonate}}{{\mathrm{Na}}_2{\mathrm{CO}}_3\left(\mathrm{aq}\right)}$