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Standard XII
Physics
Nucleus: Common Terms
Name the proc...
Question
Name the process represented below:
(a)
235
92
U
+
1
0
n
⟶
141
56
B
a
+
92
36
K
r
+
3
1
0
n
+
200
M
e
V
(b)
2
1
H
+
3
1
H
⟶
4
2
H
e
+
1
0
n
+
17.6
M
e
V
(c)
63
29
C
u
+
4
2
H
e
+
400
M
e
V
⟶
37
17
C
l
+
14
1
1
H
+
16
1
0
n
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Solution
a)
235
92
U
+
1
0
n
⟶
141
56
B
a
+
92
36
K
r
+
3
1
0
n
+
200
M
e
v
(Nuclear fission)
b)
2
1
H
+
3
1
H
⟶
4
2
H
c
+
1
0
n
+
17.6
M
e
v
(Nuclear fusion)
c)
63
29
C
u
+
4
2
H
e
400
M
e
v
−
−−−−−
→
37
17
C
l
+
14
1
1
H
+
16
1
0
n
(Nuclear fission)
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0
Similar questions
Q.
The nuclear reaction,
63
29
C
u
+
4
2
H
e
⟶
37
17
C
l
+
14
1
1
H
+
16
1
0
n
is referred to as:
Q.
Write the complete nuclear reactions:
(a)
9
4
B
e
+
4
2
H
e
⟶
12
6
C
+
______
(b)
3
1
H
⟶
3
2
H
e
+
________
(c)
14
7
N
+
4
2
H
e
⟶
17
8
O
+
_______
(d)
235
92
U
+
1
0
n
⟶
92
38
S
r
+
X
e
+
3
1
0
n
(e)
7
3
L
i
+
1
0
n
⟶
2
4
2
H
e
+
_______
(f)
238
92
U
+
_______
⟶
239
92
U
⟶
239
93
N
p
+
_______
(g)
14
7
N
+
1
0
n
⟶
________
+
3
1
H
(h)
7
3
L
i
+
_______
⟶
8
4
B
e
+
γ
-radiations
(i)
2
1
H
+
______
⟶
4
2
H
e
+
1
0
n
(j)
27
13
A
l
+
1
0
n
⟶
24
11
N
a
+
_______
(k)
27
13
A
l
+
4
2
H
e
⟶
________
+
1
1
H
(l)
235
92
U
+
1
0
n
⟶
_______
+
137
52
T
e
+
97
40
Z
r
(m)
86
34
S
e
⟶
_______
+
2
0
−
1
e
Q.
Fill in the blank space with a suitable answer selected from the list below. Write only the letter
(
A
,
B
C
,
…
,
e
t
c
)
of the correct answer in the blanks.
Answer
(
i
)
12
6
C
+
1
1
H
⟶
13
7
N
............
(
i
i
)
27
13
A
l
+
1
1
H
⟶
24
12
M
g
+
4
2
H
e
...........
(
i
i
i
)
235
92
U
+
1
0
n
⟶
140
56
B
a
+
93
36
K
r
+
3
1
0
n
............
(
i
v
)
75
33
A
s
+
2
1
H
⟶
56
25
M
n
+
9
1
1
H
+
12
1
0
n
............
(
v
)
2
1
H
+
3
1
H
⟶
4
2
H
e
+
1
0
n
...........
Answers:
A: Projectile capture
B: Spallation
C: Fusion
D: Projectile capture and particle emission
E: Fission
Select the correct answers according to the given codes.
Q.
Calculate the mass loss in the following:
2
1
H
+
3
1
H
⟶
4
2
H
e
+
1
0
n
Given the masses:
2
1
H
=
2.014
a
m
u
,
3
1
H
=
3.016
a
m
u
;
4
2
H
e
=
4.004
a
m
u
,
1
0
n
=
1.008
a
m
u
.
Q.
Calculate the
Q
-value of the reaction;
6
3
L
i
+
1
0
n
⟶
4
2
H
e
+
3
1
H
Given:
6
3
L
i
=
6.015126
a
m
u
,
4
2
H
e
=
4.002604
a
m
u
3
1
H
=
3.016049
a
m
u
,
1
0
n
=
1.008665
a
m
u
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