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Question

Name the product obtained in the following reaction?
CH3−CH2−CH2Pent−1−ene−CH=CH2(BH3)2−−−−−−→H2O2/OH−?

A
Pentan1ol
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B
Pentan3ol
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C
Pentan2ol
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D
2methyl butan2ol
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Solution

The correct option is C Pentan1ol
Hydroboration-oxidation reaction at alkene gives alcohol by Anti-Markovnikoff's addition.
Thus OH will go to less substituted C of the alkene thus Pent-1-ene will give Pent-1-ol as:
CH3CH2CH2CH=CH2H2O2/H+−−−−−B2H6CH3CH2CH2CH2CH2OH
option A is correct.

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