Name the products formed and write an equation when ethyne is added to the following in an inert solvent :
(a) chlorine, (c) iodine,
(b) bromine, (d) hydrogen.
(e) excess of hydrochloric acid.
(a) Ethyne in an inert solvent of carbon tetrachloride adds chlorine to change into 1,2- dichloro ethene with carbon-carbon double bond, and then to an 1,1,2,2-tetrachloro ethane with carbon-carbon single bond.
CH≡CH + Cl2 Inert solvent CCl4−−−−−−−−−−−→ CHCl=CHCl + excess Cl2 1,2−Dichloro ethene→CHCl2−CHCl2 1,1,2,2−Tetrachloro ethane
(b) Ethyne in an inert solvent of carbon tetrachloride adds bromine to change into 1,2-dibromo ethene and then to 1,1,2,2 -tetrabromo ethane .
CH≡CH + Br2 Inert solvent CCl4−−−−−−−−−−−→ CHBr=CHBr + excess Br2 1,2−Dibromo ethene→CHCl2−CHCl2 1,1,2,2−Tetrabromo ethane
(c) Iodine reacts slowly in the presence of alcohol to form 1,2-di-iodo ethene.
CH≡CH + I2 Inert solvent CCl4−−−−−−−−−−−→ CHI=CHI1,2−Di iodo ethene
(d) In the presence of nickel, platinum or palladium ethyne change to ethene and then to ethane.
CH≡CH + H2 Pd/C−−−→ CH2=CH2 + H2 Raney−Ni−−−−−−→ CH3−CH3
(e) excess of hydrochloric acid
CH≡CH + HCl Inert solvent CCl4−−−−−−−−−−−→ CH2=CHCl Chloro ethene excess HCl −−−−−−−−−−−−−−−−→Slow / Markovnikov′s ruleCH3−CHCl2 1,1−Dichloro ethane