Name the reactants and products in the following skeletal equation and balance them.
(ii) $N_{2} + H_{2} \to N H_{3}$

Open in App

Solution

The skeletal equation is: $N_{2} + H_{2} \to N H_{3}$
Reactants are nitrogen and hydrogen, the product is ammonia

Count the number of atoms of each element.

To equalize $N$ , multiply ${N H}_{3}$ by $2$

$N_{2} + H_{2} \to 2 N H_{3}$

To equalize $H$ , multiply $H_{2}$ by $3$ .

$N_{2} + 3 H_{2} \to 2 N H_{3}$
Hence, the equation is balanced.

Suggest Corrections

Similar questions

F e + H_{2} O \to F e_{3} O_{4} + H_{2}

N a + H_{2} O \to N a O H + H_{2}

N_{2} + H_{2} \to {N H}_{3}

1. Balance the equations. Write the name of all reactants and products.

1. S+ H₂SO₄→ SO₂ + H₂O

2. Al + Fe₂O₃→ Al₂O₃+ Fe

3. Fe + H2S04→Fe2(SO4)3 + H2

4. C2H6+ O2→CO2 + H₂O

5. KOH + H3PO4→K3PO4 + K3PO4

6. SnO2+ H2→Sn + H₂O

NH3+ O2→NO + H₂O

Join BYJU'S Learning Program

Explore more

Join BYJU'S Learning Program