Name the reactants and products in the following skeletal equation and balance them.
(iv) $F e + H_{2} O \to F e_{3} O_{4} + H_{2}$

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Solution

The skeletal equation is:
$F e + H_{2} O \to F e_{3} O_{4} + H_{2}$
Reactants are iron and water, the products are ferric oxide and hydrogen.

Count the number of atoms of each element.

To equalize $F e$ , multiply $F e$ by $3$

$3 F e + H_{2} O \to F e_{3} O_{4} + H_{2}$

To equalize $O$ , multiply $H_{2} O$ by $4$ .

$3 F e + 4 H_{2} O \to F e_{3} O_{4} + H_{2}$

To equalize $H$ , multiply $H_{2}$ by $4$ .

$3 F e + 4 H_{2} O \to F e_{3} O_{4} + 4 H_{2}$
Hence, the equation is balanced.

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