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Question

Name the reducing agent, oxidising agent, substance oxidised and substance reduced in the following redox reaction:

CrO23+2Al2Cr+AlO23


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Solution

  • Oxidation means loss of electron in this oxidation state increases.
  • Reduction means gain of electron in this oxidation state decreases.
  • The one who gets oxidised act as a reducing agent and the one who get reduced act as an oxidising agent.
  • Reaction:

CrO23+2Al2Cr+AlO23
(Chromium oxide) (Aluminium) (Chromium) (Aluminium oxide)

  • Calculation of oxidation state:

CrO23 AlO23

Oxidation state of Cr will be: Oxidation state of Al will be:

Let x be the oxidation number of Cr Let x be the oxidation number of Al

Oxidation state of O is -2 Oxidation state of O is -2

so for CrO23 2x+3(-2)=0 so for AlO23 2x+3(-2)=0

2x=6 2x=6

x=+3 x=+3

Oxidation state of Cr in CrO23 is +3. Oxidation state of Al in AlO23 is +3.


⦁ Here oxidation state of Al in Al is 0and that of Cr in CrO23 is+3 at reactant side but oxidation state of Al in AlO23is +3 and that of Cr in Cr is 0 at product side.
⦁ So, we can say that Al is getting oxidised since its oxidation number is increasing from 0 to +3 and CrO23is getting reduced since its oxidation number is decreasing from +3 to 0.
⦁ The one who gets oxidised act as a reducing agent and the one who get reduced act as an oxidising agent.
⦁ So here Al is a reducing agent and CrO23is an oxidising agent.


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