Question

Name two oxidising agents that will oxides ${\mathrm{SO}}_2$ into ${\mathrm{H}}_2{\mathrm{SO}}_4$

Answer 1

The two oxidizing agents that will oxides ${\mathbf{SO}}_{\mathbf{2}}$ into ${\mathbf{H}}_{\mathbf{2}}{\mathbf{SO}}_{\mathbf{4}}$ are ${\mathbf{Cl}}_{\mathbf{2}}$ and ${\mathbf{H}}_{\mathbf{2}}{\mathbf{O}}_{\mathbf{2}}$

1. When ${\mathrm{SO}}_2$ gas is passed through chlorine$\mathbf{\left(}{\mathbf{Cl}}_{\mathbf{2}}\mathbf{\right)}$ water, then the Sulphuric acid$\mathbf{\left(}{\mathbf{H}}_{\mathbf{2}}{\mathbf{SO}}_{\mathbf{4}}\mathbf{\right)}$ is formed.

$$\begin{gathered} {\mathrm{SO}}_2\left(\mathrm{g}\right)+{\mathrm{Cl}}_2\left(\mathrm{g}\right)+2{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)\to 2\mathrm{HCl}\left(\mathrm{aq}\right)+{\mathrm{H}}_2{\mathrm{SO}}_4\left(\mathrm{aq}\right)+\mathrm{Heat} \\ \mathrm{Sulphur}\mathrm{Chlorine}\mathrm{Water}\mathrm{Hydrogen}\mathrm{Sulphuric} \\ \mathrm{dioxide}\mathrm{gas}\mathrm{chloride}\mathrm{acid} \end{gathered}$$

2. When ${\mathrm{SO}}_2$ gas react with Hydrogen peroxide$\mathbf{\left(}{\mathbf{H}}_{\mathbf{2}}{\mathbf{O}}_{\mathbf{2}}\mathbf{\right)}$ then the Sulphuric acid$\mathbf{\left(}{\mathbf{H}}_{\mathbf{2}}{\mathbf{SO}}_{\mathbf{4}}\mathbf{\right)}$ is formed.

$$\begin{gathered} {\mathrm{SO}}_2\left(\mathrm{g}\right)+{\mathrm{H}}_2{\mathrm{O}}_2\left(\mathrm{aq}\right)\to {\mathrm{H}}_2{\mathrm{SO}}_4\left(\mathrm{aq}\right) \\ \mathrm{Sulphur}\mathrm{Hydrogen}\mathrm{Sulphuric} \\ \mathrm{dioxide}\mathrm{gas}\mathrm{peroxide}\mathrm{acid} \end{gathered}$$

Thus, the oxidizing agents that will oxides ${\mathrm{SO}}_2$ into ${\mathrm{H}}_2{\mathrm{SO}}_4$ are ${\mathrm{Cl}}_2$ and ${\mathrm{H}}_2{\mathrm{O}}_2$.